Global 1940 & 1943 Expansions Game Reports

@SuperbattleshipYamato

Finished the first game:

2023-8-13-World-War-II-Global-1940-2nd-Edition.tsvg

The game was certainly unique and spiced up from the original rules. It’s quite biased towards the Axis, with the “cannot move into pro-Allied territories while the Soviets and/or the Americans are neutral” is crippling.

I definitely could’ve been more creative as Japan, but overall it was still a fun and unique game.

@general-6-stars Yes, I would like to see that.

@baron-Münchhausen

I reviewed the 2 hits Battleship values to 2.5 multiplier factor.
It is an approximation but this is easier to use this value if you need to assess between two naval fleet during a live game with no AACalc allowed.

It is based on the very even (almost 50%-50% survival equilibrium ) combat between 1 Destroyer @2 and 1 Cruiser @3 against 1 Battleship, 2 hits @4.
http://calc.axisandallies.org/?mustland=0&abortratio=0&saveunits=0&strafeunits=0&aInf=&aArt=&aArm=&aFig=&aBom=&aTra=&aSub=&aDes=&aCru=&aCar=&aBat=1&adBat=&dInf=&dArt=&dArm=&dFig=&dBom=&dTra=&dSub=&dDes=1&dCru=1&dCar=&dBat=&ddBat=&ool_att=Bat-Inf-Art-AArt-Arm-Sub-SSub-Des-Fig-JFig-Cru-Bom-HBom-Car-dBat-Tra&ool_def=Bat-Inf-Art-AArt-Arm-Bom-HBom-Sub-SSub-Des-Car-Cru-Fig-JFig-dBat-Tra&battle=Run&rounds=&reps=10000&luck=pure&ruleset=AA1942&territory=&round=1&pbem=

1 Destroyer @2 and 1 Cruiser @3
5 pips * 2 hits = 10 pips*hits

1 Battleship, 2 hits @4.
4 pips * 1 BB worth 2.5 hits = 10 pips*hits

Damn written texts, we cannot ear sarcastic undertone.
😊😊😊

Hi Erocco,
these numbers are based on a formula found during Classic time by Dauvio Vann and his friends, then improved and adjusted to better fit the need of Second Edition units. Here is one link in House Rule:
http://www.axisandallies.org/forums/index.php?topic=40346.msg1684954#msg1684954

Below, you get the whole formula and a short explanation:

@Baron:

@Dauvio:

It came to my attention that one of my formulas are already out there that I discovered 30 years ago.
http://www.axisandallies.org/forums/index.php?action=profile;u=185969 has also discovered the formula P^2*N=S
And just for fun you can try these formulas also. S/P^2=N. √(S/N)=P
P=POINTS
N=NUMBER OF UNITS
S=STRENGTH OF ONE KIND OF UNITS IN A TERRITORY
This formula should replace the punch formula. It is much better then the punch formula.

Now the next formula is (P100)/(C^26)=S
P=POINTS
C=COST
S=STRENGTH OF THE UNIT BASED ON COST
With this formula you can also price units according to their strength. √((P100)/(S6))=C
This formula is for points. (S*(C^2*6))/100=P

For better results for some of these formulas, have all your units cost ten times then what they are. These are some of the VANN FORMULAS I came up 30 years ago.

If you have any questions about these formulas, please ask.

I found how you can get the main part of Vann formula or Baron-Larrymarx according to a specific unit as benchmark.

I took the Fighter A3 D4 C10 and I wanted to convert into Tank A3 D3 C6 as benchmark (Baron-Larrymarx formula).

Then I saw what I did.

Power (of attacking Fighter): A3 * C6 (cost of Tank)/C10 (cost of Fg) * 1 Hit Point C6 (cost of Tank)/C10 (cost of Fg) = 1.08
You can reduce this equation because (cost of Tank)(cost of Tank)/ (cost of Fg)*(cost of Fg) is same to
(cost of Tank) IPCs^2 / (cost of Fg) IPCs^2 and give a simple ratio.

C6^2*A3/C10^2 = 1.08
36 squared IPCs 3 Power * 1 Hit /100 squared IPCs = 1.08 PowerHit Point

This explained what is hidden in Baron-Larrymarx formula:
Offence or defence strength factor= 36*Power/Cost^2.

The whole Enigma formula is
Refence unit Cost^2Power of the actual unit1 HP/Cost of the actual unit^2

So, the Basic offence or defence strength factor result (1.08, in this case) is express in Power*Hit Point
1^2*Power (of a given unit)*1 hit/Cost (of this same given unit)^2

And this formula can be adapt according to any benchmark, for instance a 1 IPC unit:
131 hit/10^2 = 0.300

And this is a very small number. That’s why Vann formula:
Strength= (Power100)/(Cost^26)

add an arbitrary 1001/6= 16.667…
So, 16.667131 hit/10^2 = 0.5
And this would provide the Fighter strength attack factor based on an hypothetical benchmark unit of √16.667 = 4.0825 IPCs.
A 5 IPCs revised Tank in Vann formula gives a Strength : 16.66731 hit/5^2 = 2.00 powerhit

Can you elaborate on the ship calculations?

Destroyer strength: .30144/8^2  = 0.675
Cruiser    strength: .60144/12^2= 0.600
Battleship strength: .701442.618/20^2 = 0.660

These numbers means that Destroyer is the most optimized unit for combat to buy for each IPC invested, then it is battleship and finally Cruiser.
Said otherwise, Cruiser is sub-optimal for the cost.
3 DDs C8 A3 D3 (A9 D9, 3 hits) will be stronger than 2 Cruisers C12 A6 D6 (A12 D12, 2 hits) if you can use a Battlecalc to test D10-sided values.

From stronger to weaker for 120 IPCs basis:
15 DDs A3 D3 (A45 D45)
6 BBs A7 D7 (A42 D42)
10 CAs A6 D6 (A60 D60)

Place 1 partisan in each axis controlled empty territory of Russia. Defends at 1.

Air Transport planes will make it so much easier to get that Egypt NO for Germany.  In a number of our games Germany never gets that one because they have no transports in the Med (actually no naval presence period) and too often the Italians are using their transports too much to keep sending troops over from Italy to Africa to keep fighting the Brits and don’t have time to ferry over any Germans.  Plus, if the Brits have fighters about, then it can be dangerous for a German land unit just sitting on an Italian transport waiting to be ferried over to Egypt.  A lot of the time Italy keeps having to replace transports because of British air power and not enough naval protection.

If Germany had an air transport plane, they could wait until Italy captured Egypt and just fly a couple of guys down there then send the plane back to Germany.

Keep up the good work.