2nd edition rules make no mention of this, in fact they state that each AA gun in the territory may fire up to 3 shots.
So if you have 2 AA guns and 1 fighter attacks you would roll 1 dice for each AA gun… 2 dice. <–The correct answer is 1 dice. Number of attacking aircraft =1, 2 AA guns x3 = 6, 1 is the smaller number so it’s the answer.
If you have 2 AA guns and 2 fighters attack you would roll 2 dice for each AA gun … 4 dice. <— The correct answer is 2 dice. Number of attacking aircraft =2, 2 AA guns x3 = 6, 2 is the smaller number so it’s the answer.
If you have 2 AA guns and 4 fighters attack you would max out at 3 for each AA gun… 6 dice. <— The correct answer is 4 dice. Number of attacking aircraft = 4, 2 AA guns x3 = 6, 4 is the smaller number so it’s the answer.
Seems that simple to me. <— not to be a smart ass but that’s not a true statement either. You seemed to have missed on understanding the rule.
Some other examples: 12 attacking aircraft vs. 2 AA guns = 6 dice.
1 attacking aircraft vs. 12 AA guns = 1 dice.
7 attacking aircraft vs. 3 AA guns = 7 dice.