A&A Anniversary King Size

Taht is good to know.
If you ever wanted a game with members on this site, there is one every three months in Derbyshire. PM Private Panic or look in the Events thread.

You read it, so there must be people out there that r interested

Wow - huge help - Thank you!  And I feel like an idiot because I have that rulebook already downloaded and never noticed they were all in there.  Thanks!

Also…
All units are expendable, if the expenditure accomplishes something. Most units will be expended, but the challenge is to have them go in a way that they gave their money’s worth. Another important aspect of the game, which should be apparrent to a veteran player, or one with intelligence, is shielding of units. Some units (the more expensive ones) need to be protected by the less expensive ones. Infantry need to take hits for tanks, Destroyers and Cruisers should take hits for carriers… etc. Being able to scrape your expensive and better units out of a fight is essential for continuing operations and saving money. Make your enemy bleed more than you do.

You sir, encapsulate the spirit of the game!  I can’t say that I’d do the same… (I went so far as to slap some paint and decals on my minis), but at the end of the day - I’m with ya.  I did apply clear tape to my AAA50 box though - kinda laminated in a cheap way, but it travels with me on occasion (over the Atlantic in a suitcase).

You call others “die hard” players?  Perhaps, but in my book you’re the step up, the “hardcore” player!

@CalmDragon:

@Woodstock:

Another one:

IJN?

Initial Japanese Navy?

Close, try Imperial

Got ya…makes  a lot more sense…d’oh.

@shifty:

What kind of “program” are you writing?  What equation/algorithm are you using?

It’s written in BlitzMax. The source below should (hopefully :)) not be too hard to understand - if you have questions, feel free to ask:

' Compares 2nd ed. A&A tech dev cost/rate with Anniv. ed. A&A ' 20 turns to test; record turn number that a total of 2 breakthroughs were achieved.  Test 1 & 2 rolls/turn. ' If two breakthroughs aren't achieved, "turn 0" is recorded (ignored for graphing & turn average) ' (When going for two breakthroughs, two aren't achieved in about 2% for both 2nd and Anniv.) Strict Local breakthroughs, totalCost, turn, totalTurns Local answer[21], prefix$, graph$ Local breakthroughLimit = 2 For Local rolls = 1 To 2 ' actual rolls for 2nd Ed, Researchers for Anniv. Print;Print; Print rolls + " Tech Roll(s)/Researcher(s) per Turn:" Print; Print "2nd Edition" totalCost = 0 totalTurns = 0 For Local c = 0 To 20 answer[c] = 0 Next For Local test = 1 To 100000 ' a hundred thousand tests for accuracy breakthroughs = 0 turn = 0 While breakthroughs < breakthroughLimit And turn <= 20 turn :+ 1 totalCost :+ rolls * 5 ' each roll costs 5 IPCs For Local c = 1 To rolls If Rand(6) = 6 Then breakthroughs :+ 1 Next Wend totalTurns :+ turn If turn > 20 Then answer[0] :+ 1 Else answer[turn] :+ 1 EndIf Next ' display results For Local c = 1 To 20 graph = "" ' divide results by 1000 so each asterisk represents one percent For Local cc = 1 To Int(answer[c]/1000.0 + .5) graph :+"*" Next If c < 10 Then prefix = " " Else prefix ="" ' extra space for single digits Print prefix + c + " " + graph Next Print "Avg turn = " + totalTurns / 100000.0 Print "Avg cost = " + totalCost / 100000.0 Print; Print "Anniversary Edition" totalCost = 0 totalTurns = 0 For Local c = 0 To 20 answer[c] = 0 Next Local researchers ' researchers accumulate from turn to turn For Local test = 1 To 100000 researchers = 0 breakthroughs = 0 turn = 0 While breakthroughs < breakthroughLimit And turn <= 20 turn :+ 1 totalCost :+ rolls * 5 ' each researcher costs 5 IPCs researchers :+ 1 * rolls ' accumulate 1 researcher per "roll" Local success For Local c = 1 To researchers If Rand(6) = 6 Then success = True ' only one regardless of # of sixes rolled Next If success Then researchers = 0 ' eliminate accumulated researchers when successful breakthroughs :+ 1 EndIf Wend totalTurns :+ turn If turn > 20 Then answer[0] :+ 1 Else answer[turn] :+ 1 EndIf Next ' display results For Local c = 1 To 20 graph = "" ' divide results by 1000 so each asterisk represents one percent For Local cc = 1 To Int(answer[c]/1000.0 + .5) graph :+"*" Next If c < 10 Then prefix = " " Else prefix ="" ' extra space for single digits Print prefix + c + " " + graph Next Print "Avg turn = " + totalTurns / 100000.0 Print "Avg cost = " + totalCost / 100000.0 Next

I release it into the public domain (modify it as desired/convert it to the language of your choice).  breakthroughLimit is initially set for 2, which generated the first set of graphs in this thread (I hand-rounded the accuracy to a single decimal place when copy/pasting results in the thread). Setting it to 1 (i.e. stopping after getting one breakthrough) produced the second set above. I also made another, slightly tweaked version to generate the “only buy Researchers on turn 1” version for wodan46.

No, it can’t.  Just passing through the Philippines sea zone counts as two movements (one in, one out), since the fighter doesn’t actually enter the island territory.  However, attacking the Philippines territory would cost two extra movements: one to enter the Philippines from the sea zone and another to exit the Philippines back into the sea zone.

Your example would look like this:

1. Japan to sea zone 62.
2. Sea zone 62 to sea zone 60.
3. Sea zone 60 to sea zone 50.
4. Sea zone 50 to Philippine Islands.
5. Philippine Islands to sea zone 50.
6. Sea zone 50 to sea zone 49 (carrier).

As you can see, a standard fighter would be out of movement at the Philippines, with nowhere to land, making this an illegal move.

However, if the same fighter took off from a carrier in the Japan sea zone, it could attack the Philippines and land on a carrier (perhaps the same one) in the Philippines sea zone:

Sea zone 62 (carrier) to sea zone 60.
Sea zone 60 to sea zone 50.
Sea zone 50 to Philippine Islands.
Philippine Islands to sea zone 50 (carrier).

Each time a plane crosses a boundary between spaces (whether between land or sea or both), it uses one movement point.