@Alsch91:
Spendo, the fact that a 2-interceptor would make you think twice about sending a bomber against a fighter is exactly the point.
If I’ve got interceptors then you should have to send escorts.� The way it is now, interceptors are nearly useless in all but the most extreme cases.
1 IPC Reduction
1 16.67% 0.17
2 16.67% 0.33
3 16.67% 0.50
4 16.67% 0.67
5 16.67% 0.83
6 16.67% 1.00
IPC Cost to Defender per SBR 5.5
Event P LAC IL ID IC NC
Ftr @1 (Miss), AA (Miss Both) 76.39% $0 $0 $11 $8 $8
Ftr @1 (Miss), AA (1 Hit) 4.63% $15 $1 $6 $0 -$0
Ftr @1 (Miss), AA (2 Hit) 2.31% $30 $1 $0 $0 -$1
Ftr @1 (Hit), AA (Miss Both) 15.28% $15 $2 $6 $1 -$1
Ftr @1 (Hit), AA (1 Hit) 0.93% $30 $0 $0 $0 -$0
Ftr @1 (Hit), AA (2 Hit) 0.46% $30 $0 $0 $0 -$0
IPC Cost to Attacker $4 $9 $5
P = Probability of Event occurring
LAC = Value of Aircraft Lost
IL = P * LAC which when summed to $4 is the cost of the SBR to Germany
ID = Damage to the Major IC based off the probability of rolling a 1 through 6 (its rounded from 5.5)
IC = P * ID which when summed to $9 is the cost of the SBR to London
NC = IC - IL which when summed to $5 and cross footed ( $9-$4 ) is the actual damage the SBR causes net of all probabilities.
Event P LAC IL ID IC NC
Ftr @2 (Miss), AA (No Hit) 61.11% $0 $0 $11 $7 $7
Ftr @2 (Miss), AA (1 Hit) 3.70% $15 $1 $6 $0 -$0
Ftr @2 (Miss), AA (2 Hit) 1.85% $30 $1 $0 $0 -$1
Ftr @2 (Hit), AA (No Hit) 30.56% $15 $5 $6 $2 -$3
Ftr @2 (Hit), AA (1 Hit) 1.85% $30 $1 $0 $0 -$1
Ftr @2 (Hit), AA (2 Hit) 0.93% $30 $0 $0 $0 -$0
IPC Cost $7 $9 $2
P = Probability of Event occurring
LAC = Value of Aircraft Lost
IL = P * LAC which when summed to $7 is the cost of the SBR to Germany
ID = Damage to the Major IC based off the probability of rolling a 1 through 6 (its rounded from 5.5)
IC = P * ID which when summed to $9 is the cost of the SBR to London
NC = IC - IL which when summed to $2 and cross footed ( $9 - $7 ) is the actual damage the SBR causes net of all probabilities.
So the change from interceptors rolling @1 versus rolling @2 is approximately 3 IPC to Germany in a 2 Bombers versus 1 Ftr scenario; an entirely possible scenario on G2.
Probabilities were derived from:
(5/6) = Miss from Ftr @1 - meaning you rolled anything but a 1
(1/6) = Hit from Ftr @1 - meaning you rolled a 1
(33/36) = Miss from AA @1 - meaning you rolled anything but a 1 on either die
(2/36) = 1 Hit from AA @1 - meaning the die roll was a 2 and a 1 or a 1 and a 2
(1/36) = 2 Hit from AA @1 - meaning you rolled snake eyes
(4/6) = Miss from Ftr @2 - meaning you rolled anything but a 1 or 2
(2/6) = Hit from Ftr @2 - meaning you rolled a 1 or 2
So in example, a Ftr @1 scoring a hit and AA misses both = 2/6 * 33/36 = 15.28% probability this occurs sequentially.
That probability is multiplied by the value of aircraft lost (either 15 or 30) and also by the most probable value a bomber would score for a successful SBR (5.5 per Bomber).
Then you just subtract the cost from the benefit and get the actual value (or loss) in a German SBR on London of 2 Bombers versus 1 Ftr.
Something else to realize is that this is just a probability evaluation of if you should do something. A positive number indicates a gain, a negative number indicates a loss - obviously you don’t want to do something that is a loss unless there are unmeasurable advantages to gain from it.
The relevant range of IPC damage for both bombers escaping interceptors is as low as 6 IPC or as high as 16 IPC which you have approximately 6% of accomplishing against a single Ftr @1. It drops to just over a 5% chance against a single Ftr @2.
A better expectation, therefore, is to assume +/-1 from 9 IPC if both bombers get through which accounts for just shy of 50% of all probable outcomes.
Edit: Apologies for the terrible column formatting.