Its not the type of hit and run interaction i would call a “good idea” The definition of hit and run is to attack for a short duration because you are in the advantage for this. If you were not in the advantage, like sending one tank attacking 300 infantry, this is not hit and run, but rather hit and die.
Nice try but won’t help you. I don’t play battles where i would significantly approach any situation like that. Also, its not hit and run anyway. I don’t play with low luck, but made it easy for you on the math so you and others can see based on any standardized empirical and accepted way of doing studies like this. What is also possible is i can kill more so its not an argument to say in a hit and run situation that your mechs can kill more than the tanks, because the tanks can also do more harm and based on the numbers they have a greater propensity to do so.
The point is that if you are not at risk to lose any units BEYOND the inf and artillery screen, there is NO difference in the combat effectiveness of 4 tanks compared to 6 mechs, or 6 mechs compared to 2 tanks and 3 mechs.
No. Again thats not what has been proven. In overall effectiveness the combined arms aspects of tanks boosting tactical bombers making it a 4 vs. a 2 shows with no doubt that based on attack and defense the overall winner is the mixed tank force with combined arms.
These are all equal IPC arrangements of mechs and tanks. AS LONG AS THE HITS ARE NOT BEING TAKEN ON THE MECHS AND/OR TANKS, they are EVEN when supporting a hit-and run attack.
If hits ARE being taken on mechs and/or tanks, the army that has more mechs relative to tanks is STRONGER
Your point is mechs are stronger and i proved that false. Also, hits are not being taken on tanks because as stated 5,000,000 time before i am no entertaining an attack that would do that in order to prove that tank force is better than mech force.
Again the Math proves otherwise.
Quote from: Imperious Leader on March 15, 2011, 09:12:18 pm
So what really happens in this example is nothing is proven, so we need another example:
No, it proves that they are EQUAL in terms of attack strength. It proves the only inequality is how many hits each arrangement can take. Mechs can take more hits, losing less IPC and less attack value per hit. Mechs are sometimes even to tanks, sometimes better, but not worse.
What is proved was in this example no determination, so i made a new example THAT SHOWED THAT TANK MIXED FORCE IN HIT AND RUN WINS AGAINST MECH MIXED FORCE, OF WHICH YOU IGNORED BECAUSE AGAIN THE MATH PROVED YOU WRONG.
Quote from: Imperious Leader on March 15, 2011, 09:12:18 pm
Example #2
YOU ATTACKING:
1. 8 infantry, 3 mech, 4 artillery, 3 fighters, 3 tactical bombers, 2 bomber= 55
12+6+8+9+12+8=55
ME DEFENDING
2. 8 infantry, 2 tanks, 4 artillery, 3 fighters, 3 tactical, 2 bomber=55
16+8+8+12+9+2=55
Result: NO CHANGE
reversed:
YOU DEFENDING:
1. 8 infantry, 3 mech, 4 artillery, 3 fighters, 3 tactical bombers, 2 bomber= 53
16+6+8+12+9+2=53
ME ATTACKING:
2. 8 infantry, 2 tanks, 4 artillery, 3 fighters, 3 tactical, 2 bomber=57
12+8+8+9+12+8=57
I HAVE AN ADVANTAGE OF +4 IN ONE ROUND.
Absolutely Brilliant!
First of all, you claim to be after “empirical” evidence in measuring which is a better hit-and run ATTACKER. Why when comparing who is a better ATTACKER do you have one DEFEND against the other’s ATTACK.
Because all i need to do is prove my point in one round. If the odds are to my advantage in any round, my hit and run attack continues. Again you want to take me down the example where my tanks are exchanged and i told you 50 times before , that this is hit and run. I fight as long as my advantage remains and you are losing more in net IPC then me. Thats why it is one round in this example. Nice try.
We need to look at how each would fare ATTACKING against a CONSISTENT defensive force. HOW do we measure the usefeulness of a force to do a hit-and-run ATTACK when it is DEFENDING?Huh?
NO we don’t, i know thats what you like to do since the math proves my point because this is a hit and run example, not “lets get my tanks killed in battle, so the numbers move over to mantlefans favor”
Now repeat: HIT AND RUN, HIT AND RUN….
TO DO THIS PURPOSEFULLY YOU NEED A CONSTANT DEFENSE
No rather to make the numbers swing to your favor you want something other than hit and run, and as i stated 50 times before hit and run is only a value while the loses are less for the tank side, than for the mech side.
It’s so easy! PICK A DEFENSIVE FORCE. Have the mech force fight that defense. Have the tank force fight the SAME defense.
So you need
1. A defense
2. A mech-supported attack force
3. A tank supported attack force
4 (If you want) a mech/tank mixed attack force
Yes i did that with 4-5 examples and each time it makes your point fail. Read prior examples…
You need a constant defense to compare both sets of attackers against, otherwise the comparison gets bogged down in considerations about the differences in defense value for bombers for example, which really has nothing to do with what they attack at.
I was wondering when you would start crying about bombers, but alas again i only need to prove my point using the same total IPC per each side, and i did.
Second, your math is off for this unscientific multiple-variable exercise anyways.
8 inf (with 4 arty support)=12, 3 mech=6, 4art=8, 3 ftr=9, 3 tac (BOOSTED BY FTRS!!)=12, 2 Bmb=8
12+6+8+3+9+12+8= 58, NOT 57. FIFTY-EIGHT
Wait. :-D now please slip in another THREE to make the math better? Ahh that feels better? Nice try. 55 Bud. LOL
Attacking:
8 inf=16, 4 arty=8, 2 tanks=6, 3 ftr=12. 3 tac=9, 2bmb=2
16+8+6+12+9+2= 53, NOT 55. FIFTY-THREE
Bombers attack at 1? what ruleset you using? :-D
I think you are confused about attack or defense. I assume you MEANT DEFENSE?
8 inf=16, 4 arty=8, 2 tanks=6, 3 ftr=12. 3 tac=9, 2bmb=2
16+8+6+12+9+2= 53 RIGHT.
The reversal:( YOU ATTACKING)
8 infantry, 3 mech, 4 artillery, 3 fighters, 3 tactical bombers, 2 bomber=
12+6+8+9+12+8=55
Defender also has 53 (only difference is 3 mechs instead of 2 tanks; 2x3=3x2)
Attacker ALSO has 58 (only difference is 2 tanks instead 3 of mechs; 2x3=3x2)
If you do this scientifically rather than either make up numbers or mess up the math like you are doing, the best way to see who is a more effective ATTACKER is to have the mech-supported force fight a defender, then have the tank-supported fight the SAME DEFENDER. NOT THE MECH ARMY. NOT THE TANK ARMY (unless you want them BOTH to fight a mech army or BOTH fight a tank army)
When comparing who is the better ATTACKER, they need to fight an IDENTICAL DEFENSE. It really doesn’t matter what you pick, as long as Mech force attacks the defending force, and the tank force attacks the SAME defending force. Not the mech-supported-attacking tank-supported or vice versa, the fact that bmbs and infantry have different attack and defense values draws attention away from how mechs or tanks would fit the role of mobile support.
NO. Thats not the form of study because the tank force needs its combined arms component to be greater than the mech force that does not boost anything. IN hit and run tactics, i am using the greater potency of tanks with the combined arms to show that tank force are greater than mech force in these hit and run tactics.
YOU just want to make the study into a stripped tank vs mech fight, which is not what this is about. I said from the start that as long as a tank force with plenty of combined arms wins against a mech force, i was proven right.
Example #4
Me Attacking:
10 infantry, 6 artillery, 8 tanks, 8 tactical bombers, 4 fighters=96
16+12+24+32+12=96
You Defending:
10 infantry, 6 artillery, 12 mechs, 8 tactical bombers, 4 fighters=
20+12+24+24+12=92
I win with +4
REVERSED:
Me Defending:
10 infantry, 6 artillery, 8 tanks, 8 tactical bombers, 4 fighters=96
20+12+24+24+16=96
You Attacking:
10 infantry, 6 artillery, 12 mechs, 8 tactical bombers, 4 fighters=92
16+12+24+12+16+12=92
Again i win with +4 advantage.
Ok this is getting boring. I proved my point.