The good times are over

So I played a quick game against a friend last weekend (we agreed it was experimental and would not count towards our scoreboard).

I was the axis and picked two national advantages: naval night-fighting and nazi scientists.

The allied player insisted on also having two national advantages, so he picked colonial garrison and flying fortresses (I forget the name, it’s the non-LHTR national advantage; US bombers are immune to AA).

Colonial Garrison gave me a lot of problems!  He placed the IC in India, which I went for right away, but the allies managed to trade it for a few turns, and then the US player waited till I was in a bad situation and bought two factories in china and sinkian.

The battleship advantage was not that great.  It was fun for a couple of battles, but then the US player just avoided my battleships.  I was a few turns from opening the suez canal, and my fleet was prepared against africa, but the US player was going to provide quite a hassle.

The game ended prematurely; I suspect I would eventually have lost.  The nazi scientists got me a tech upgrade only after 10 tech buys.

@bigchris:

@gnasape:

Thanks bigchris, what if we assume that the dice rolls of the attacker and defenders are two separate events?

16 rolls for attacker, 7 rolls for defender.

sure, that’s fine.  as long as you are separating the rolls based on some arbitrary labeling and not based on their values, you can test any group/sub-group you like.

Ho: the dice are uniformly distributed
Ha: the dice are not uniformly distributed

Attacker: 6,5,6,5,4,6,5,6,6,4,3,5,4,6,3,6
histogram for entire sequence (16 rolls total)
6s: 6666666
5s: 5555
4s: 444
3s: 33
2s:
1s:

pearson chi-square test:
with 16 rolls, we expect 16/6=2.67 rolls in each bin according to Ho.
(7 - 2.67)^2 / 2.67 +
(4 - 2.67)^2 / 2.67 +
(3 - 2.67)^2 / 2.67 +
(2 - 2.67)^2 / 2.67 +
(0 - 2.67)^2 / 2.67 +
(0 - 2.67)^2 / 2.67 = 13.25

chi-square value = 13.25
degrees-of-freedom = 5
Probability (One-Tailed): 0.0211

that is, for the attacker, if Ho is in fact true, the probability of getting results as or more extreme than these is 0.0211.  These data are sufficient evidence (at the 5% level) to reject Ho and adopt Ha.

Defender: 2,2,1,3,4,2,1
histogram for entire sequence (7 rolls total)
6s:
5s:
4s: 4
3s: 3
2s: 222
1s: 11

pearson chi-square test:
with 7 rolls, we expect 7/6=1.17 rolls in each bin according to Ho.
(0 - 1.17)^2 / 1.17 +
(0 - 1.17)^2 / 1.17 +
(1 - 1.17)^2 / 1.17 +
(1 - 1.17)^2 / 1.17 +
(3 - 1.17)^2 / 1.17 +
(2 - 1.17)^2 / 1.17 = 5.857

chi-square value = 5.857
degrees-of-freedom = 5
Probability (One-Tailed): 0.3204

that is, for the defender, if Ho is in fact true, the probability of getting results as or more extreme than these is 0.3204.  this is insufficient evidence to reject Ho.  therefore, we do not reject Ho.

Thanks, I am basing it as usually the attacker’s dice roll is submitted first than defender.

Every Nation gets 2 NAs + 1 Tech.

Allies pick 1 more NA and 1 more tech for the nation(s) of their choice. (ie both don’t have to go to the same country.)
Axis pick 1 more NA and 1 more tech for each nation.

That could be fun!

I am not aware of any paratroopers in any game, except as an optional rule for “3rd Edition”, the Hasbro CD-Rom

good way to delay japan is to play tradeoff with them in Ind (Uk), Yak (Rus), Sin (Us) with whatever inf is available. In the end he will beat you at tradeoffs, but its better than going to an arms race between Russia (getting somewhat pressure by Ger) and Japan. That will definately delay him/her.

And leaving that DST alive and the Suez open invites another problem…
A pretty nice UK fleet roaming the Indian Ocean.  By UK2 it can be 2 DST’s, an AC, 2 FIGs, 2 TRNs and a sub.  That puts them on par with Japan’s remaining fleet after Pearl…

Thanks a bunch.  Ill give that a shot. :wink:

Come on now and sign up!  See the posting in the “Events” thread under “Finding Players” and let’s get rolling!!  A&A Revised rocks, and this tournament will be a blast!