I am open for games. First choice AA50 1942 using Triple A
But, AAR, aka 4th edition is ok, too
Rolls: 1@1 2@2 1@3; Total Hits: 11@1: (6)2@2: (4, 6)1@3: (1)
Rolls: 1@2 1@3; Total Hits: 11@2: (3)1@3: (2)
Rolls: 1@1 2@2 1@3; Total Hits: 21@1: (1)2@2: (6, 1)1@3: (5)
Rolls: 1@2 1@3; Total Hits: 01@2: (3)1@3: (5)
Rolling 8d6:
(1, 2, 2, 2, 3, 4, 5, 6)
Rolls: 3@1 1@3; Total Hits: 23@1: (2, 6, 1)1@3: (2)
Rolls: 3@1; Total Hits: 13@1: (5, 5, 1)
Rolling 1d6:
(2)
Rolls: 2@5; Total Hits: 12@5: (4, 6)
Rolls: 2@5; Total Hits: 22@5: (2, 1)
Rolling 1d6:
(4)
Rolling 1d6:
(1)
Rolls: 2@1 1@3; Total Hits: 02@1: (4, 5)1@3: (5)
Rolls: 1@2; Total Hits: 01@2: (5)
Rolls: 2@1 1@3; Total Hits: 12@1: (2, 1)1@3: (6)
Rolls: 1@2; Total Hits: 11@2: (2)
Rolls: 2@1 1@3; Total Hits: 12@1: (2, 3)1@3: (3)
Rolls: 1@2; Total Hits: 01@2: (4)
Attacker:
Rolling 2d6:
(2, 2)
Defender:
Rolling 2d6:
(1, 2)
aaa 3@1 1@3
;aaa 3@1 4@4 5@3;
If you replace the “;” by “:”, it will give:
Rolls: 3@1 4@4 5@3; Total Hits: 63@1: (6, 1, 1)4@4: (5, 4, 5, 5)5@3: (6, 3, 6, 2, 1)
Rolling 1d6:
(2)
Rolls: 2@1 3@3 1@4; Total Hits: 22@1: (3, 4)3@3: (4, 5, 3)1@4: (3)
Rolls: 3@2 2@3; Total Hits: 33@2: (3, 2, 3)2@3: (2, 2)
Rolls: 2@1 3@3 1@4; Total Hits: 22@1: (4, 3)3@3: (3, 4, 4)1@4: (3)
Rolls: 3@2 2@3; Total Hits: 33@2: (2, 3, 1)2@3: (5, 2)
Rolls: 2@1 3@3 1@4; Total Hits: 12@1: (1, 2)3@3: (5, 5, 4)1@4: (5)
Rolls: 3@2 2@3; Total Hits: 33@2: (6, 3, 1)2@3: (3, 1)