Ok… I have more to do than read every post on these forums but as far as I’ve been, allweneed is totally correct. The average cost to get a technology if you buy a number x of die every turn is given by the relation (cost by turn)/(probability to get a tech) where the probability is expressed by a number between 0 and 1. In mathematical terms, we have costaverage = 5*x/(1-(5/6)x).
-Buying 1 die a turn gives an average of 5*1/(1-(5/6)1) = 30 IPCs.
-Buying 2 dice a turn gives an average of 5*2/(1-(5/6)2) = 32.7 IPCs.
-Buying 6 dice a turn gives an average of 5*6/(1-(5/6)6) = 45.1 IPCs.
@Holden:
@allweneedislove:
assuming you only roll 1 die at a cost of 5ipc per die roll then the average number of rolls to acquire a tech is 6. 5ipc * 6rolls = 30ipc = average cost to acquire tech.
This is not how averages are calculated. The question is largely meaningless. If you really wanted to calculate the average cost then you’d have to record every game of Axis and Allied played and find out how many IPC’s were spent to aquire tech by the multitude of players. Then you’d have to add those numbers all together and divide by the total number of players.
You’re just making up some arbitrary fomula that sort of seems that it should fit and calling it the average cost. Then your claiming that your average cost cannot be disputed and building an entire thread around it.
No, allweneed is right. Holden, your method doesn’t work in theory unless you try it an infinite number of times. Good luck… :wink:
In conclusion, yes, techs really suck in this game… :-(