• are you aware that 0.99999999 repeating is equal to 1 ? watch this

    say that o.999999 repeating equals x

    10x = 9.9999999999 repeating

    subtract 1x from both sides and you get
    9x = 9.000000000

    divide both sides by 9 and you get

    x = 1

    weird huh?


  • @FleetCommander:

    are you aware that 0.99999999 repeating is equal to 1 ? watch this

    say that o.999999 repeating equals x

    10x = 9.9999999999 repeating

    subtract 1x from both sides and you get
    9x = 9.000000000

    divide both sides by 9 and you get

    x = 1

    weird huh?

    no,
    if you subtract 1 from 9.9 repeating, you get 8.9 repeating.


  • Yeah that is neat. One of those counter intuitive math things that doesnt seem right but is. =p


  • It’s kind of like the thing where you can get 1=2. I forget how that went, but I’ll see if I can’t figure it out again.


  • @FleetCommander:

    are you aware that 0.99999999 repeating is equal to 1 ?

    Yes, they are equal. It’s like saying the limit of 1-x as x approaches 0 equals 1.


  • @Grigoriy:

    It’s kind of like the thing where you can get 1=2.

    Let x=y, then
    xy=x^2
    xy-y^2=x^2-y^2
    y(x-y)=(x+y)(x-y)
    y=x+y
    y=y+y
    y=2y
    1=2
    :lol:


  • Well…

    1/9 in decimal is 0.1111…
    Thus, 0.999… is 9*1/9 = 1
    not too suprising :)

    @Dirt:

    Let x=y, then

    y(x-y)=(x+y)(x-y)
    y=x+y

    The good old “divide by zero” trick :)

    nice is alos when you use only the positive solution of a square root and forget about the negative one.


  • nice is alos when you use only the positive solution of a square root and forget about the negative one.

    I didn’t forget, I just…decided not to include it. Yeah. :roll:

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